can you foreach() two arrays at once ?

On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
wrote:

>J. Frank Parnell wrote:
>> Hello,
>> So, I was wondering how to do this:
>>
>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>> }
>>
>> Thanks,
>
>No.
>
>However, you can use "each" to do the same thing, i.e.
>
>reset $array1;
>reset $array2;
>
>for ((list($key1, $val1) = each($array1)) &&
> (list($key2, $val2) = each($array2)) {
>// $key1 and val1 contain the key and value for an element in $array1
>// $key2 and val2 contain the key and value for an element in $array2
>// Do your stuff here
>}
>
>It will stop as soon as you run out of elements in either array.

Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
go thru all of both, even if one runs out?
 >> Stay informed about: can you foreach() two arrays at once ? 

J. Frank Parnell wrote:
> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
> wrote:
>
>> J. Frank Parnell wrote:
>>> Hello,
>>> So, I was wondering how to do this:
>>>
>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>> }
>>>
>>> Thanks,
>> No.
>>
>> However, you can use "each" to do the same thing, i.e.
>>
>> reset $array1;
>> reset $array2;
>>
>> for ((list($key1, $val1) = each($array1)) &&
>> (list($key2, $val2) = each($array2)) {
>> // $key1 and val1 contain the key and value for an element in $array1
>> // $key2 and val2 contain the key and value for an element in $array2
>> // Do your stuff here
>> }
>>
>> It will stop as soon as you run out of elements in either array.
>
> Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
> go thru all of both, even if one runs out?
>

What do you want to do with the array which runs out? And what do you
want to do with the array with items left?



--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex RemoveThis @attglobal.net
==================
 >> Stay informed about: can you foreach() two arrays at once ? 

On Sep 7, 8:49 am, J. Frank Parnell wrote:
> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
> wrote:
>
>
>
> >J. Frank Parnell wrote:
> >> Hello,
> >> So, I was wondering how to do this:
>
> >> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
> >> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
> >> }
>
> >> Thanks,
>
> >No.
>
> >However, you can use "each" to do the same thing, i.e.
>
> >reset $array1;
> >reset $array2;
>
> >for ((list($key1, $val1) = each($array1)) &&
> > (list($key2, $val2) = each($array2)) {
> >// $key1 and val1 contain the key and value for an element in $array1
> >// $key2 and val2 contain the key and value for an element in $array2
> >// Do your stuff here
> >}
>
> >It will stop as soon as you run out of elements in either array.
>
> Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
> go thru all of both, even if one runs out?


if (count ($arr1) > count($arr2)) {
$len = count($arr1);
}
else {
$len = count($arr2);
}

Now

foreach($i=0; $i < $len; $i++) {

list($key1, $val1) = @each($arr1);
list($key2, $val2) = @each($arr2);
}

What about this?
I have not checked this.

http://satya61229.blogspot.com/
 >> Stay informed about: can you foreach() two arrays at once ? 

On Sep 7, 12:28 pm, Satya wrote:
> On Sep 7, 8:49 am, J. Frank Parnell wrote:
>
>
>
> > On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
> > wrote:
>
> > >J. Frank Parnell wrote:
> > >> Hello,
> > >> So, I was wondering how to do this:
>
> > >> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
> > >> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
> > >> }
>
> > >> Thanks,
>
> > >No.
>
> > >However, you can use "each" to do the same thing, i.e.
>
> > >reset $array1;
> > >reset $array2;
>
> > >for ((list($key1, $val1) = each($array1)) &&
> > > (list($key2, $val2) = each($array2)) {
> > >// $key1 and val1 contain the key and value for an element in $array1
> > >// $key2 and val2 contain the key and value for an element in $array2
> > >// Do your stuff here
> > >}
>
> > >It will stop as soon as you run out of elements in either array.
>
> > Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
> > go thru all of both, even if one runs out?
>
> if (count ($arr1) > count($arr2)) {
> $len = count($arr1);}
>
> else {
> $len = count($arr2);
>
> }
>
> Now
>
> for($i=0; $i < $len; $i++) {
>
> list($key1, $val1) = @each($arr1);
> list($key2, $val2) = @each($arr2);
>
> }
>
> What about this?
> I have not checked this.
>
> http://satya61229.blogspot.com/

There I used "foreach" instead of "for".
 >> Stay informed about: can you foreach() two arrays at once ? 

On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
wrote:

>J. Frank Parnell wrote:
>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>> wrote:
>>
>>> J. Frank Parnell wrote:
>>>> Hello,
>>>> So, I was wondering how to do this:
>>>>
>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>> }
>>>>
>>>> Thanks,
>>> No.
>>>
>>> However, you can use "each" to do the same thing, i.e.
>>>
>>> reset $array1;
>>> reset $array2;
>>>
>>> for ((list($key1, $val1) = each($array1)) &&
>>> (list($key2, $val2) = each($array2)) {
>>> // $key1 and val1 contain the key and value for an element in $array1
>>> // $key2 and val2 contain the key and value for an element in $array2
>>> // Do your stuff here
>>> }
>>>
>>> It will stop as soon as you run out of elements in either array.
>>
>> Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
>> go thru all of both, even if one runs out?
>>
>
>What do you want to do with the array which runs out? And what do you
>want to do with the array with items left?

I figured the var that ran out would just be empty while the other var is still
listing, eaching, etc. It might be handy to be able to specify a default value
instead of empty, like   for the table exapmle above. Looks like I could
just stick a little if() in Satya's code.
 >> Stay informed about: can you foreach() two arrays at once ? 

J. Frank Parnell wrote:
> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
> wrote:
>
>> J. Frank Parnell wrote:
>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>> wrote:
>>>
>>>> J. Frank Parnell wrote:
>>>>> Hello,
>>>>> So, I was wondering how to do this:
>>>>>
>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>> }
>>>>>
>>>>> Thanks,
>>>> No.
>>>>
>>>> However, you can use "each" to do the same thing, i.e.
>>>>
>>>> reset $array1;
>>>> reset $array2;
>>>>
>>>> for ((list($key1, $val1) = each($array1)) &&
>>>> (list($key2, $val2) = each($array2)) {
>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>> // Do your stuff here
>>>> }
>>>>
>>>> It will stop as soon as you run out of elements in either array.
>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so that it will
>>> go thru all of both, even if one runs out?
>>>
>> What do you want to do with the array which runs out? And what do you
>> want to do with the array with items left?
>
> I figured the var that ran out would just be empty while the other var is still
> listing, eaching, etc. It might be handy to be able to specify a default value
> instead of empty, like   for the table exapmle above. Looks like I could
> just stick a little if() in Satya's code.
>
>

OK, then try this:

reset $array1;
reset $array2;

for (($val1 = each($array1)) || ($val2 = each($array2)) {
if ($val1) { // false if at the end
// $val1['key'] contains the key
// $val1['value'] contains the value
echo $val1['key'] . '=>' $val1['value'];
}
else
echo ' ';
if ($val2) { // false if at the end
// $val2['key'] contains the key
// $val2['value'] contains the value
echo $val2['key'] . '=>' $val2['value'];
}
else
echo ' ';
}


--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex.TakeThisOut@attglobal.net
==================
 >> Stay informed about: can you foreach() two arrays at once ? 

Jerry Stuckle wrote:
> J. Frank Parnell wrote:
>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>>
>> wrote:
>>
>>> J. Frank Parnell wrote:
>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>>
>>>> wrote:
>>>>
>>>>> J. Frank Parnell wrote:
>>>>>> Hello,
>>>>>> So, I was wondering how to do this:
>>>>>>
>>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>>> }
>>>>>>
>>>>>> Thanks,
>>>>> No.
>>>>>
>>>>> However, you can use "each" to do the same thing, i.e.
>>>>>
>>>>> reset $array1;
>>>>> reset $array2;
>>>>>
>>>>> for ((list($key1, $val1) = each($array1)) &&
>>>>> (list($key2, $val2) = each($array2)) {
>>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>>> // Do your stuff here
>>>>> }
>>>>>
>>>>> It will stop as soon as you run out of elements in either array.
>>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so
>>>> that it will
>>>> go thru all of both, even if one runs out?
>>> What do you want to do with the array which runs out? And what do
>>> you want to do with the array with items left?
>>
>> I figured the var that ran out would just be empty while the other
>> var is still
>> listing, eaching, etc. It might be handy to be able to specify a
>> default value
>> instead of empty, like   for the table exapmle above. Looks like
>> I could
>> just stick a little if() in Satya's code.
>>
>>
>
> OK, then try this:
>
> reset $array1;
> reset $array2;
>
> for (($val1 = each($array1)) || ($val2 = each($array2)) {
> if ($val1) { // false if at the end
> // $val1['key'] contains the key
> // $val1['value'] contains the value
> echo $val1['key'] . '=>' $val1['value'];
> }
> else
> echo ' ';
> if ($val2) { // false if at the end
> // $val2['key'] contains the key
> // $val2['value'] contains the value
> echo $val2['key'] . '=>' $val2['value'];
> }
> else
> echo ' ';
> }
>
>

Sorry - that should be:

for (($val1 = each($array1)) || ($val2 = each($array2))) {

Missed an extra paren at the end.

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex.TakeThisOut@attglobal.net
==================
 >> Stay informed about: can you foreach() two arrays at once ? 

On Fri, 07 Sep 2007 15:01:24 -0400, Jerry Stuckle
wrote:

>Jerry Stuckle wrote:
>> J. Frank Parnell wrote:
>>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>>>
>>> wrote:
>>>
>>>> J. Frank Parnell wrote:
>>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>>>
>>>>> wrote:
>>>>>
>>>>>> J. Frank Parnell wrote:
>>>>>>> Hello,
>>>
>> reset $array1;
>> reset $array2;
>>
>> for (($val1 = each($array1)) || ($val2 = each($array2)) {
>> if ($val1) { // false if at the end
>> // $val1['key'] contains the key
>> // $val1['value'] contains the value
>> echo $val1['key'] . '=>' $val1['value'];
>> }
>> else
>> echo ' ';
>> if ($val2) { // false if at the end
>> // $val2['key'] contains the key
>> // $val2['value'] contains the value
>> echo $val2['key'] . '=>' $val2['value'];
>> }
>> else
>> echo ' ';
>> }
>>
>>
>
>Sorry - that should be:
>
>for (($val1 = each($array1)) || ($val2 = each($array2))) {
>
>Missed an extra paren at the end.

Thanks again for the help, however, I still get:
Parse error: syntax error, unexpected ')', expecting ';' in
/web/sites/asdf/asdf.com/_impexp/test.php on line 55

Isnt there supposed to be 3 expressions in a FOR? I tried with semicolons here
and there, but couldnt get it.

current code:
for (($val1 = each($users)) || ($val2 = each($newusers))) {
if ($val1) { // false if at the end
// $val1['key'] contains the key
// $val1['value'] contains the value
echo $val1['key'] . '=>' $val1['value'];
}
else
echo ' ';
if ($val2) { // false if at the end
// $val2['key'] contains the key
// $val2['value'] contains the value
echo $val2['key'] . '=>' $val2['value'];
}
else
echo ' ';
}
 >> Stay informed about: can you foreach() two arrays at once ? 

J. Frank Parnell wrote:
> On Fri, 07 Sep 2007 15:01:24 -0400, Jerry Stuckle
> wrote:
>
>> Jerry Stuckle wrote:
>>> J. Frank Parnell wrote:
>>>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>>>>
>>>> wrote:
>>>>
>>>>> J. Frank Parnell wrote:
>>>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>>>>
>>>>>> wrote:
>>>>>>
>>>>>>> J. Frank Parnell wrote:
>>>>>>>> Hello,
>>> reset $array1;
>>> reset $array2;
>>>
>>> for (($val1 = each($array1)) || ($val2 = each($array2)) {
>>> if ($val1) { // false if at the end
>>> // $val1['key'] contains the key
>>> // $val1['value'] contains the value
>>> echo $val1['key'] . '=>' $val1['value'];
>>> }
>>> else
>>> echo ' ';
>>> if ($val2) { // false if at the end
>>> // $val2['key'] contains the key
>>> // $val2['value'] contains the value
>>> echo $val2['key'] . '=>' $val2['value'];
>>> }
>>> else
>>> echo ' ';
>>> }
>>>
>>>
>> Sorry - that should be:
>>
>> for (($val1 = each($array1)) || ($val2 = each($array2))) {
>>
>> Missed an extra paren at the end.
>
> Thanks again for the help, however, I still get:
> Parse error: syntax error, unexpected ')', expecting ';' in
> /web/sites/asdf/asdf.com/_impexp/test.php on line 55
>
> Isnt there supposed to be 3 expressions in a FOR? I tried with semicolons here
> and there, but couldnt get it.
>
> current code:
> for (($val1 = each($users)) || ($val2 = each($newusers))) {
> if ($val1) { // false if at the end
> // $val1['key'] contains the key
> // $val1['value'] contains the value
> echo $val1['key'] . '=>' $val1['value'];
> }
> else
> echo ' ';
> if ($val2) { // false if at the end
> // $val2['key'] contains the key
> // $val2['value'] contains the value
> echo $val2['key'] . '=>' $val2['value'];
> }
> else
> echo ' ';
> }
>
>
>

Sorry - it should be a 'while' loop, not a 'for' loop.

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex.TakeThisOut@attglobal.net
==================
 >> Stay informed about: can you foreach() two arrays at once ? 

On Fri, 07 Sep 2007 17:57:00 +0200, J. Frank Parnell
wrote:

> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>
> wrote:
>
>> J. Frank Parnell wrote:
>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>
>>> wrote:
>>>
>>>> J. Frank Parnell wrote:
>>>>> Hello,
>>>>> So, I was wondering how to do this:
>>>>>
>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>> }
>>>>>
>>>>> Thanks,
>>>> No.
>>>>
>>>> However, you can use "each" to do the same thing, i.e.
>>>>
>>>> reset $array1;
>>>> reset $array2;
>>>>
>>>> for ((list($key1, $val1) = each($array1)) &&
>>>> (list($key2, $val2) = each($array2)) {
>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>> // Do your stuff here
>>>> }
>>>>
>>>> It will stop as soon as you run out of elements in either array.
>>>
>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so
>>> that it will
>>> go thru all of both, even if one runs out?
>>>
>>
>> What do you want to do with the array which runs out? And what do you
>> want to do with the array with items left?
>
> I figured the var that ran out would just be empty while the other var
> is still
> listing, eaching, etc. It might be handy to be able to specify a
> default value
> instead of empty, like   for the table exapmle above. Looks like I
> could
> just stick a little if() in Satya's code.

Or an array_pad() on the smaller one...


--
Rik Wasmus
 >> Stay informed about: can you foreach() two arrays at once ? 

On Fri, 07 Sep 2007 18:47:47 +0200, "Rik Wasmus"
wrote:

>On Fri, 07 Sep 2007 17:57:00 +0200, J. Frank Parnell
>wrote:
>
>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>>
>> wrote:
>>
>>> J. Frank Parnell wrote:
>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>>
>>>> wrote:
>>>>
>>>>> J. Frank Parnell wrote:
>>>>>> Hello,
>>>>>> So, I was wondering how to do this:
>>>>>>
>>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>>> }
>>>>>>
>>>>>> Thanks,
>>>>> No.
>>>>>
>>>>> However, you can use "each" to do the same thing, i.e.
>>>>>
>>>>> reset $array1;
>>>>> reset $array2;
>>>>>
>>>>> for ((list($key1, $val1) = each($array1)) &&
>>>>> (list($key2, $val2) = each($array2)) {
>>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>>> // Do your stuff here
>>>>> }
>>>>>
>>>>> It will stop as soon as you run out of elements in either array.
>>>>
>>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so
>>>> that it will
>>>> go thru all of both, even if one runs out?
>>>>
>>>
>>> What do you want to do with the array which runs out? And what do you
>>> want to do with the array with items left?
>>
>> I figured the var that ran out would just be empty while the other var
>> is still
>> listing, eaching, etc. It might be handy to be able to specify a
>> default value
>> instead of empty, like   for the table exapmle above. Looks like I
>> could
>> just stick a little if() in Satya's code.
>
>Or an array_pad() on the smaller one...

Well, neither of these are working, Jerry's (both scripts) have a syntax error,
(missing ; and I cant figure where it wants it) and Satya's outputs:
0 Array 0 0
1 Array 1 1
2 Array 2 2
3 Array 3 3
4 4
 >> Stay informed about: can you foreach() two arrays at once ? 

On Fri, 07 Sep 2007 19:13:57 +0200, Jerry Stuckle
wrote:

> J. Frank Parnell wrote:
>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>>
>> wrote:
>>
>>> J. Frank Parnell wrote:
>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>>
>>>> wrote:
>>>>
>>>>> J. Frank Parnell wrote:
>>>>>> Hello,
>>>>>> So, I was wondering how to do this:
>>>>>>
>>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>>> }
>>>>>>
>>>>>> Thanks,
>>>>> No.
>>>>>
>>>>> However, you can use "each" to do the same thing, i.e.
>>>>>
>>>>> reset $array1;
>>>>> reset $array2;
>>>>>
>>>>> for ((list($key1, $val1) = each($array1)) &&
>>>>> (list($key2, $val2) = each($array2)) {
>>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>>> // Do your stuff here
>>>>> }
>>>>>
>>>>> It will stop as soon as you run out of elements in either array.
>>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so
>>>> that it will
>>>> go thru all of both, even if one runs out?
>>> What do you want to do with the array which runs out? And what do you
>>> want to do with the array with items left?
>> I figured the var that ran out would just be empty while the other
>> var is still
>> listing, eaching, etc. It might be handy to be able to specify a
>> default value
>> instead of empty, like   for the table exapmle above. Looks like I
>> could
>> just stick a little if() in Satya's code.
>>
>
> OK, then try this:
>
> reset $array1;
> reset $array2;
>
> for (($val1 = each($array1)) || ($val2 = each($array2)) {
> if ($val1) { // false if at the end
> // $val1['key'] contains the key
> // $val1['value'] contains the value
> echo $val1['key'] . '=>' $val1['value'];
> }
> else
> echo ' ';
> if ($val2) { // false if at the end
> // $val2['key'] contains the key
> // $val2['value'] contains the value
> echo $val2['key'] . '=>' $val2['value'];
> }
> else
> echo ' ';
> }

Hmmz, haven't tried it, but won't the second list argument only be run
when the first fails, so in essence 2 foreach loops after one another?


--
Rik Wasmus
 >> Stay informed about: can you foreach() two arrays at once ? 

Rik Wasmus wrote:
> On Fri, 07 Sep 2007 19:13:57 +0200, Jerry Stuckle
> wrote:
>
>> J. Frank Parnell wrote:
>>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>>>
>>> wrote:
>>>
>>>> J. Frank Parnell wrote:
>>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>>>
>>>>> wrote:
>>>>>
>>>>>> J. Frank Parnell wrote:
>>>>>>> Hello,
>>>>>>> So, I was wondering how to do this:
>>>>>>>
>>>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>>>> }
>>>>>>>
>>>>>>> Thanks,
>>>>>> No.
>>>>>>
>>>>>> However, you can use "each" to do the same thing, i.e.
>>>>>>
>>>>>> reset $array1;
>>>>>> reset $array2;
>>>>>>
>>>>>> for ((list($key1, $val1) = each($array1)) &&
>>>>>> (list($key2, $val2) = each($array2)) {
>>>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>>>> // Do your stuff here
>>>>>> }
>>>>>>
>>>>>> It will stop as soon as you run out of elements in either array.
>>>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so
>>>>> that it will
>>>>> go thru all of both, even if one runs out?
>>>> What do you want to do with the array which runs out? And what do
>>>> you want to do with the array with items left?
>>> I figured the var that ran out would just be empty while the other
>>> var is still
>>> listing, eaching, etc. It might be handy to be able to specify a
>>> default value
>>> instead of empty, like   for the table exapmle above. Looks like
>>> I could
>>> just stick a little if() in Satya's code.
>>>
>>
>> OK, then try this:
>>
>> reset $array1;
>> reset $array2;
>>
>> for (($val1 = each($array1)) || ($val2 = each($array2)) {
>> if ($val1) { // false if at the end
>> // $val1['key'] contains the key
>> // $val1['value'] contains the value
>> echo $val1['key'] . '=>' $val1['value'];
>> }
>> else
>> echo ' ';
>> if ($val2) { // false if at the end
>> // $val2['key'] contains the key
>> // $val2['value'] contains the value
>> echo $val2['key'] . '=>' $val2['value'];
>> }
>> else
>> echo ' ';
>> }
>
> Hmmz, haven't tried it, but won't the second list argument only be run
> when the first fails, so in essence 2 foreach loops after one another?
>
>

Nope, both if statements are in the loop. Each time through it will
process $val1 then $val2.

Your suggestion of array_pad() is also good, unless the arrays are large.

--
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex DeleteThis @attglobal.net
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 >> Stay informed about: can you foreach() two arrays at once ?