option values with php foreach not working

When I run this code locally I get, in firefox, a listbox with "adam" as
the only output. Nothing else. The second array doesn't even show.

In IE, both items show but I get a warning saying "invalid argument -
foreach".
The second array shows up after the warning.

What am I missing?

Dear Santa,

Please bring lots of coal! We need the heat!




<select name="menu1" size="10">
<option value="101">adam</option>

<?php

$myArray="(1,2,3,4,5)";
foreach ($myArray as $myItem) {
echo "<option value='$myItem'>$myItem</option>\n"; }

$arr = array("one", "two", "three");
foreach ($arr as $key => $value) {
echo "Key: $key; Value: $value<br />\n";
}


?>


</select>

On Fri, 24 Dec 2010 19:58:56 -0700, richard wrote:

> When I run this code locally I get, in firefox, a listbox with "adam" as
> the only output. Nothing else. The second array doesn't even show.
>
> In IE, both items show but I get a warning saying "invalid argument -
> foreach".
> The second array shows up after the warning.
>
> What am I missing?
>
> Dear Santa,
>
> Please bring lots of coal! We need the heat!
>
>
>
>
> <select name="menu1" size="10">
> <option value="101">adam</option>
>
> <?php
>
> $myArray="(1,2,3,4,5)";
> foreach ($myArray as $myItem) {
> echo "<option value='$myItem'>$myItem</option>\n"; }
>
> $arr = array("one", "two", "three");
> foreach ($arr as $key => $value) {
> echo "Key: $key; Value: $value<br />\n";
> }
>
>
> ?>
>
>
> </select>

Notice I had the second array where it shouldn't be and moved it out of
that part.

Still I get a warning for an invalid argument foreach.